C++中的Lambda表达式¶
C++ 11引入了lambda表达式,允许使用内联函数,这些函数可以用于不打算重用的短代码片段,因此不需要名称。在最简单的形式中,lambda表达式可以定义如下:
C++ 11引入了lambda表达式,允许使用内联函数,这些函数可以用于不打算重用的短代码片段,因此不需要名称。在最简单的形式中,lambda表达式可以定义如下:
// C++ program to demonstrate lambda expression in C++
#include <bits/stdc++.h>
using namespace std;
// Function to print vector
void printVector(vector<int> v)
{
// lambda expression to print vector
for_each(v.begin(), v.end(), [](int i)
{
std::cout << i << " ";
});
cout << endl;
}
int main()
{
vector<int> v {4, 1, 3, 5, 2, 3, 1, 7};
printVector(v);
// below snippet find first number greater than 4
// find_if searches for an element for which
// function(third argument) returns true
vector<int>:: iterator p = find_if(v.begin(), v.end(), [](int i)
{
return i > 4;
});
cout << "First number greater than 4 is : " << *p << endl;
// function to sort vector, lambda expression is for sorting in
// non-increasing order Compiler can make out return type as
// bool, but shown here just for explanation
sort(v.begin(), v.end(), [](const int& a, const int& b) -> bool
{
return a > b;
});
printVector(v);
// function to count numbers greater than or equal to 5
int count_5 = count_if(v.begin(), v.end(), [](int a)
{
return (a >= 5);
});
cout << "The number of elements greater than or equal to 5 is : "
<< count_5 << endl;
// function for removing duplicate element (after sorting all
// duplicate comes together)
p = unique(v.begin(), v.end(), [](int a, int b)
{
return a == b;
});
// resizing vector to make size equal to total different number
v.resize(distance(v.begin(), p));
printVector(v);
// accumulate function accumulate the container on the basis of
// function provided as third argument
int arr[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
int f = accumulate(arr, arr + 10, 1, [](int i, int j)
{
return i * j;
});
cout << "Factorial of 10 is : " << f << endl;
// We can also access function by storing this into variable
auto square = [](int i)
{
return i * i;
};
cout << "Square of 5 is : " << square(5) << endl;
}
输出:
4 1 3 5 2 3 1 7
First number greater than 4 is : 5
7 5 4 3 3 2 1 1
The number of elements greater than or equal to 5 is : 2
7 5 4 3 2 1
Factorial of 10 is : 3628800
Square of 5 is : 25
通过访问外层作用域中的变量,lambda 表达式比普通函数更强大。我们可以通过三种方式从外层作用域捕获外部变量: 按引用捕获 按值捕获 按引用和值混合捕获 捕获变量的语法如下: [&]:按引用捕获所有外部变量 [=]:按值捕获所有外部变量 [a, &b]:按值捕获a,按引用捕获b 具有空捕获子句[ ]的lambda只能访问其局部变量。 以下是不同捕获方法的演示:
// C++ program to demonstrate lambda expression in C++
#include <bits/stdc++.h>
using namespace std;
int main()
{
vector<int> v1 = {3, 1, 7, 9};
vector<int> v2 = {10, 2, 7, 16, 9};
// access v1 and v2 by reference
auto pushinto = [&] (int m)
{
v1.push_back(m);
v2.push_back(m);
};
// it pushes 20 in both v1 and v2
pushinto(20);
// access v1 by copy
[v1]()
{
for (auto p = v1.begin(); p != v1.end(); p++)
{
cout << *p << " ";
}
};
int N = 5;
// below snippet find first number greater than N
// [N] denotes, can access only N by value
vector<int>:: iterator p = find_if(v1.begin(), v1.end(), [N](int i)
{
return i > N;
});
cout << "First number greater than 5 is : " << *p << endl;
// function to count numbers greater than or equal to N
// [=] denotes, can access all variable
int count_N = count_if(v1.begin(), v1.end(), [=](int a)
{
return (a >= N);
});
cout << "The number of elements greater than or equal to 5 is : "
<< count_N << endl;
}
输出:
First number greater than 5 is : 7
The number of elements greater than or equal to 5 is : 3
注意:Lambda表达式在C++ 11之后可用。